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Question
- solve: \\(\frac{x - 9}{6} = \frac{x + 7}{3}\\)
Step1: Cross - multiply the equation
Given the equation \(\frac{x - 9}{6}=\frac{x + 7}{3}\), cross - multiplying (which is based on the property that if \(\frac{a}{b}=\frac{c}{d}\), then \(a\times d=b\times c\)) gives us \(3(x - 9)=6(x + 7)\).
Step2: Expand both sides
Expand the left - hand side: \(3x-27\), and expand the right - hand side: \(6x + 42\). So the equation becomes \(3x-27 = 6x+42\).
Step3: Move the terms with x to one side and constants to the other
Subtract \(3x\) from both sides: \(3x-3x - 27=6x-3x + 42\), which simplifies to \(-27 = 3x+42\). Then subtract 42 from both sides: \(-27-42=3x+42 - 42\), so \(-69 = 3x\).
Step4: Solve for x
Divide both sides by 3: \(x=\frac{-69}{3}=-23\).
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\(x = - 23\)