Question

1. a bag contains 6 yellow marbles and 4 blue marbles. you choose a marble, put it aside, and then choose another marble. what is the probability that you choose two yellow marbles?

Explanation:

Step1: Find total marbles initially

Total marbles = 6 (yellow) + 4 (blue) = 10.
Probability of first yellow: $\frac{6}{10}$.

Step2: Find marbles after first pick

After picking one yellow, yellow left = 5, total left = 9.
Probability of second yellow: $\frac{5}{9}$.

Step3: Multiply probabilities

Probability of two yellows: $\frac{6}{10} \times \frac{5}{9} = \frac{30}{90} = \frac{1}{3}$.

Answer:

$\frac{1}{3}$