Question

18 based on the concept of periodic trends, answer the following questions for these atoms: li, be, mg, na be able to defend your answers. a. which element has the lowest electronegativity? ____ b. which element has the least metallic character? __ c. which element is the largest atom? na ____

Explanation:

Part a: Lowest Electronegativity

Electronegativity increases across a period (left to right) and decreases down a group (top to bottom). Among Li, Be, Mg, Na: Na is in Group 1 (leftmost, lower period than Li), so it has the lowest electronegativity.

Part b: Least Metallic Character

Metallic character decreases across a period (left to right) and increases down a group. Be is in Period 2, Group 2 (right of Li, above Mg/Na), so it has the least metallic character.

Part c: Largest Atom

Atomic size increases down a group (more electron shells) and decreases across a period. Na is in Period 3 (below Li/Be in Period 2, Mg in Period 3 but Na is left of Mg), so Na has the largest atomic radius.

Answer:

Na