Question

1. consider the equation $x^2 + 8x + 16 = 0$. 18a find the value of the discriminant. discriminant =

Explanation:

Step1: Recall discriminant formula

For a quadratic equation \(ax^2 + bx + c = 0\), the discriminant \(D\) is given by \(D = b^2 - 4ac\).

Step2: Identify coefficients

In the equation \(x^2 + 8x + 16 = 0\), we have \(a = 1\), \(b = 8\), and \(c = 16\).

Step3: Substitute into formula

Substitute \(a = 1\), \(b = 8\), and \(c = 16\) into the discriminant formula:
\(D = 8^2 - 4\times1\times16\)

Step4: Calculate the values

First, calculate \(8^2 = 64\) and \(4\times1\times16 = 64\). Then, \(D = 64 - 64\).

Step5: Simplify the result

\(D = 0\).

Answer:

\(0\)