Question

1. c + o₂ → co₂
2. s + o₂ → so₂
3. na₂co₃ + hcl → nacl + h₂o + co₂
4. zn + hcl → zncl₂ + h₂
5. fes + o₂ → fe₂o₃ + so₂
6. c₄h₁₀ + o₂ → co₂ + h₂o

Explanation:

Step1: Balance equation 19

The equation $C + O_2
ightarrow CO_2$ is already balanced as there is 1 carbon atom and 2 oxygen atoms on both sides.

Step2: Balance equation 20

The equation $S+O_2
ightarrow SO_2$ is already balanced with 1 sulfur atom and 2 oxygen atoms on both sides.

Step3: Balance equation 21

For $Na_2CO_3 + HCl
ightarrow NaCl+H_2O + CO_2$, balance sodium first. We need 2 moles of $NaCl$, so the balanced equation is $Na_2CO_3+2HCl = 2NaCl + H_2O+CO_2$.

Step4: Balance equation 22

For $Zn + HCl
ightarrow ZnCl_2+H_2$, balance chlorine. We need 2 moles of $HCl$, so the balanced equation is $Zn + 2HCl=ZnCl_2 + H_2$.

Step5: Balance equation 23

For $FeS+O_2
ightarrow Fe_2O_3+SO_2$, balance iron first. We need 4 moles of $FeS$, then balance sulfur and oxygen. The balanced equation is $4FeS + 7O_2=2Fe_2O_3+4SO_2$.

Step6: Balance equation 24

For $C_4H_{10}+O_2
ightarrow CO_2 + H_2O$, first balance carbon and hydrogen. We get $C_4H_{10}+\frac{13}{2}O_2 = 4CO_2+5H_2O$. Multiply through by 2 to get whole - number coefficients: $2C_4H_{10}+13O_2 = 8CO_2 + 10H_2O$.

Answer:

1. $C + O_2=CO_2$
2. $S + O_2=SO_2$
3. $Na_2CO_3+2HCl = 2NaCl + H_2O+CO_2$
4. $Zn + 2HCl=ZnCl_2 + H_2$
5. $4FeS + 7O_2=2Fe_2O_3+4SO_2$
6. $2C_4H_{10}+13O_2 = 8CO_2 + 10H_2O$