Question

19 essay 1 point
a 4.50 l sample of dry air in a cylinder exerts a pressure of 5.00 atm at a temperature of 25 °c. without a change in temperature, a piston is moved until the pressure in the cylinder is reduced to 1.00 atm. what is the volume of the gas?

Explanation:

Step1: State Boyle's Law

For constant temperature: $P_1V_1 = P_2V_2$

Step2: Identify given values

$P_1=5.00\ \text{atm}$, $V_1=4.50\ \text{L}$, $P_2=1.00\ \text{atm}$

Step3: Solve for $V_2$

Rearrange formula: $V_2 = \frac{P_1V_1}{P_2}$
Substitute values: $V_2 = \frac{5.00\ \text{atm} \times 4.50\ \text{L}}{1.00\ \text{atm}}$

Step4: Calculate final volume

$V_2 = 22.5\ \text{L}$

Answer:

$22.5\ \text{L}$