Question

1. what is the missing number in the following equation?

$1\frac{4}{9}+\frac{1}{\square}=1\frac{7}{9}$

Explanation:

Step1: Let the missing denominator be \( x \). Rewrite the equation as \( 1\frac{4}{9}+\frac{1}{x}=1\frac{7}{9} \).

First, subtract \( 1\frac{4}{9} \) from both sides: \( \frac{1}{x}=1\frac{7}{9}-1\frac{4}{9} \).

Step2: Calculate the right - hand side.

For mixed numbers with the same whole number part, we subtract the fractional parts: \( 1\frac{7}{9}-1\frac{4}{9}=\frac{7 - 4}{9}=\frac{3}{9}=\frac{1}{3} \).
Since \( \frac{1}{x}=\frac{1}{3} \), then \( x = 3 \).

Answer:

The missing number (denominator) is \( 3 \), so the fraction is \( \frac{1}{3} \), and the missing number in the box is \( 3 \).