Question

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x

y

(x,y)

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0

$\frac{1}{2}$

$(0, \frac{1}{2})$

1

$1\frac{1}{2}$

$(1, 1\frac{1}{2})$

2

$2\frac{1}{2}$

$(2, 2\frac{1}{2})$

1ymore thanisless thanx$\frac{1}{2}$

Explanation:

Step1: Identify slope from points

Take two points, e.g., $(0,\frac{1}{2})$ and $(1,1\frac{1}{2})$. Slope $m = \frac{1\frac{1}{2}-\frac{1}{2}}{1-0} = 1$.

Step2: Identify y-intercept

From $(0,\frac{1}{2})$, y-intercept $b=\frac{1}{2}$.

Step3: Form linear equation

Use $y=mx+b$: $y = 1 \cdot x + \frac{1}{2}$, which simplifies to $y$ is $x$ plus $\frac{1}{2}$, or $y$ is more than $x$ by $\frac{1}{2}$.

Answer:

$y$ is more than $x$ by $\frac{1}{2}$ (or formatted as $y = x + \frac{1}{2}$)