Question

1. \sqrt3{-81x^4y^4}

Explanation:

Step1: Factor radicand into cubes

$\sqrt[3]{-27 \cdot 3 \cdot x^3 \cdot x \cdot y^3 \cdot y}$

Step2: Separate perfect cube factors

$\sqrt[3]{-27x^3y^3} \cdot \sqrt[3]{3xy}$

Step3: Simplify perfect cube root

$-3xy\sqrt[3]{3xy}$

Answer:

$-3xy\sqrt[3]{3xy}$