Question

20$\boldsymbol{\bigcirc}$)$\overline{6801}$
divide and write remainder.

Explanation:

Step1: Assume the divisor is 20x (x is a digit, let's first consider the form 200 - 209, but actually, maybe it's a typo or the blacked part is a digit, let's assume the divisor is 201 (common 3 - digit with 20_). Let's check 6801 ÷ 201.

First, 201 × 33 = 201×30 + 201×3 = 6030 + 603 = 6633.

Step2: Subtract 6633 from 6801: 6801 - 6633 = 168. Wait, maybe the divisor is 209? No, let's think again. Wait, maybe the blacked part is 0 - 9, let's try divisor 200: 6801 ÷ 200 = 34 with remainder 1 (since 200×34 = 6800, 6801 - 6800 = 1). Wait, but the divisor is 20_ (3 digits), so 200 - 209. Let's try divisor 201: as above, remainder 168. But maybe the original problem has a typo, and the divisor is 20 (but it's 3 digits? No, the division symbol has 20_ as divisor, 3 digits. Wait, maybe the blacked part is a digit, so divisor is 20a (a is 0 - 9). Let's take a = 0: divisor 200, 6801 ÷ 200 = 34, remainder 1 (200×34 = 6800, 6801 - 6800 = 1). If a = 1, divisor 201, remainder 168. But maybe the intended divisor is 20 (two digits), but the problem shows 20_ (three digits). Wait, maybe it's a printing error, and the divisor is 20 (two digits). Let's check 6801 ÷ 20.

20 × 340 = 6800, so 6801 ÷ 20 = 340 with remainder 1.
Wait, the problem's divisor is 20_ (three digits), so let's confirm. Let's suppose the divisor is 201 (most likely 20_ with digit 1). Then:

Step1: Find how many times 201 goes into 6801. 201×33 = 6633 (as 201×30 = 6030, 201×3 = 603; 6030 + 603 = 6633)

Step2: Subtract: 6801 - 6633 = 168. So remainder 168. But maybe the divisor is 209: 209×32 = 6688, 6801 - 6688 = 113. No, this is confusing. Wait, maybe the blacked part is a 0, so divisor 200. Then 6801 ÷ 200 = 34, remainder 1 (since 200×34 = 6800, 6801 - 6800 = 1). This is more likely if it's a simple division. So let's go with divisor 200 (assuming the blacked part is 0).

Answer:

If the divisor is 200, the quotient is 34 and the remainder is 1. (If the divisor is 201, remainder is 168; but likely the intended divisor is 200 or 20, but with 20_ as 3 digits, 200 is reasonable. So remainder is 1 (for divisor 200) or 168 (for 201). But more likely, the problem has a typo and the divisor is 20 (two digits), then 6801 ÷ 20 = 340 with remainder 1. So the remainder is 1.