Question

1. $125^{2/3}$
2. $128^{5/7}$

of the base of a co

Explanation:

Step1: Simplify $125^{2/3}$

First, rewrite as root then power:
$\sqrt[3]{125}^2 = 5^2 = 25$

Step2: Simplify $128^{5/7}$

Rewrite as root then power:
$\sqrt[7]{128}^5 = 2^5 = 32$

Answer:

$125^{2/3} = 25$
$128^{5/7} = 32$