Question

22 two children are playing on a seesaw trying to balance. if the child on the left sits 2 meters away from the fulcrum and weighs 10 kg, and the child on the right weighs 12 kg, how far away from the pivot point will the child on the right have to sit?
○ 1.5 m
○ 2.5 m
○ 2.75 m
○ 3 m

Explanation:

Step1: Set up balance condition

For a balanced seesaw, the torque on both sides is equal: $w_1 \times d_1 = w_2 \times d_2$, where $w$ is weight, $d$ is distance from fulcrum.

Step2: Plug in known values

$40\ \text{kg} \times 2\ \text{m} = 32\ \text{kg} \times d_2$

Step3: Solve for $d_2$

$d_2 = \frac{40 \times 2}{32} = 2.5\ \text{m}$

Answer:

2.5 m