Question

23 a baseball player hits a ground ball to the shortstop with 350 j of kinetic energy. when the shortstop fields the ball, it has 243 j of kinetic energy. how much work did the force of friction between the ball and the ground do? \bigcirc 107 j \bigcirc 7 j \bigcirc 593 j \bigcirc 144 j

Explanation:

Step1: Apply work-energy theorem

The work done by friction equals the change in kinetic energy of the ball, expressed as:
$$W = \Delta KE = KE_f - KE_i$$

Step2: Substitute given values

Substitute $KE_i = 350\ \text{J}$ and $KE_f = 243\ \text{J}$:
$$W = 243 - 350 = -107\ \text{J}$$
The negative sign indicates the force opposes motion; the magnitude of work done is 107 J.

Answer:

107 J