Question

24/28
simplify
$(8yz)(-8y^{2}z^{3})$
$-64y^{3}z^{4}$
$y^{3}z^{4}$
$64y^{3}z^{4}$
$-64y^{1}z^{4}$

Explanation:

Step1: Multiply coefficients

$8 \times (-8) = -64$

Step2: Combine $y$ terms

$y^1 \times y^2 = y^{1+2} = y^3$

Step3: Combine $z$ terms

$z^1 \times z^3 = z^{1+3} = z^4$

Step4: Combine all parts

$-64 \times y^3 \times z^4$

Answer:

-64y³z⁴ (Option: -64y³z⁴)