Question

1. a student measured the volume of a liquid to be 215.5 ml. the correct value of the volume is 205.5 ml. what is the student’s percent error?

% error = \\(\frac{v_e - v_a}{v_a}\times100\\)
% error = \\(\frac{\text{ml}-\text{ml}}{\text{ml}}\times100\\)
% error =

1. a student calculated the density of aluminum to be 2.95 g/cm³. the actual density of aluminum is 2.70 g/cm³. what is the student’s percent error?

% error = \\(\frac{v_e - v_a}{v_a}\times100\\)
% error = \\(\frac{\text{g/cm³}-\text{g/cm³}}{\text{g/cm³}}\times100\\)
% error =

Explanation:

Step1: Identify values for problem 24

$V_E = 215.5$ mL, $V_A=205.5$ mL

Step2: Substitute values into percent - error formula

$\% error=\frac{215.5 - 205.5}{205.5}\times100=\frac{10}{205.5}\times100$

Step3: Calculate the result

$\% error\approx4.87\%$

Step4: Identify values for problem 25

$V_E = 2.95$ g/cm³, $V_A = 2.70$ g/cm³

Step5: Substitute values into percent - error formula

$\% error=\frac{2.95 - 2.70}{2.70}\times100=\frac{0.25}{2.70}\times100$

Step6: Calculate the result

$\% error\approx9.26\%$

Answer:

1. Approximately $4.87\%$
2. Approximately $9.26\%$