Question

1. 2kclo₃ → 2kcl + 6o₂

atom reactants products
k
cl
o

Explanation:

Step1: Count K atoms in reactants

There are 2 K atoms in \(2KClO_3\) as the coefficient of \(KClO_3\) is 2 and there is 1 K per \(KClO_3\) unit. So, reactants: 2.

Step2: Count K atoms in products

There are 2 K atoms in \(2KCl\) as the coefficient of \(KCl\) is 2 and there is 1 K per \(KCl\) unit. So, products: 2.

Step3: Count Cl atoms in reactants

There are 2 Cl atoms in \(2KClO_3\) as the coefficient of \(KClO_3\) is 2 and there is 1 Cl per \(KClO_3\) unit. So, reactants: 2.

Step4: Count Cl atoms in products

There are 2 Cl atoms in \(2KCl\) as the coefficient of \(KCl\) is 2 and there is 1 Cl per \(KCl\) unit. So, products: 2.

Step5: Count O atoms in reactants

There are 6 O atoms in \(2KClO_3\) as the coefficient of \(KClO_3\) is 2 and there are 3 O per \(KClO_3\) unit (\(2\times3 = 6\)). So, reactants: 6.

Step6: Count O atoms in products

There are 12 O atoms in \(6O_2\) as the coefficient of \(O_2\) is 6 and there are 2 O per \(O_2\) unit (\(6\times2=12\)). So, products: 12.

Atom	Reactants	Products
Cl	2	2
O	6	12

Answer:

Atom	Reactants	Products
Cl	2	2
O	6	12