Question

1. 2pb(no₃)₂ pb= n= o=

Explanation:

Step1: Analyze the coefficient and sub - scripts for Pb

The coefficient in front of $Pb(NO_3)_2$ is 2. Since there is 1 $Pb$ atom in each $Pb(NO_3)_2$ unit, the number of $Pb$ atoms is $2\times1 = 2$.

Step2: Analyze the coefficient and sub - scripts for N

There is 1 $N$ atom in each $NO_3$ group, and there are 2 $NO_3$ groups in each $Pb(NO_3)_2$ unit, and the coefficient of $Pb(NO_3)_2$ is 2. So the number of $N$ atoms is $2\times2\times1=4$.

Step3: Analyze the coefficient and sub - scripts for O

There are 3 $O$ atoms in each $NO_3$ group, 2 $NO_3$ groups in each $Pb(NO_3)_2$ unit, and the coefficient of $Pb(NO_3)_2$ is 2. So the number of $O$ atoms is $2\times2\times3 = 12$.

Answer:

$Pb = 2$, $N = 4$, $O = 12$