Question

q 32.) avery spun the spinner with the numbers 1 - 4 and rolled a number cube with the numbers 1 - 6. what is the probability that avery spun an even number and did not roll a 5? 1st choice 2nd choice 1 1 1 1 2 2 2 2 3 3 3 3 4 4 4 4 5 5 5 5 6 6 6 6 answer

Explanation:

Step1: Calculate probability of spinning an even number

The spinner has 4 numbers (1 - 4). Even numbers are 2 and 4. So the probability of spinning an even number $P(S_{even})=\frac{2}{4}=\frac{1}{2}$.

Step2: Calculate probability of not rolling a 5 on the die

The die has 6 numbers (1 - 6). The probability of rolling a 5 is $\frac{1}{6}$, so the probability of not rolling a 5 $P(D_{
eq5}) = 1-\frac{1}{6}=\frac{5}{6}$.

Step3: Calculate combined probability

Since the spinner - spin and die - roll are independent events, the combined probability $P = P(S_{even})\times P(D_{
eq5})$. Substitute the values: $P=\frac{1}{2}\times\frac{5}{6}=\frac{5}{12}$.

Answer:

$\frac{5}{12}$