QUESTION IMAGE
Question
37.
x =
y =
38.
x =
y =
39.
x =
y =
40.
x =
y =
41.
x =
y =
42.
x =
y =
z =
43.
x =
y =
z =
44.
x =
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45.
x =
y =
options: (2sqrt{2}), (3sqrt{3}), (\frac{4sqrt{3}}{3}), (6), (6sqrt{3}), (8sqrt{2}), (12), (12sqrt{2}), (16), (\frac{16sqrt{3}}{3}), (17sqrt{3}), (18sqrt{15}), (22sqrt{2}), (22sqrt{6}), (34), (36sqrt{5}), (44)
Problem 37
Step1: Find x via 30-60-90 ratios
$x = 17\sqrt{3}$
Step2: Find y via 30-60-90 ratios
$y = 34$
Problem 38
(Answers already provided as $x=12$, $y=12\sqrt{2}$)
Problem 39
Step1: Solve for x using tan(30°)
$\tan(30^\circ) = \frac{x}{18\sqrt{5}} \implies x = 18\sqrt{5} \times \frac{1}{\sqrt{3}} = 6\sqrt{15}$
Step2: Solve for y using cos(30°)
$\cos(30^\circ) = \frac{18\sqrt{5}}{y} \implies y = \frac{18\sqrt{5}}{\frac{\sqrt{3}}{2}} = 12\sqrt{15}$
Problem 40
Step1: Find x via 30-60-90 triangle
$x = 12 \times \frac{\sqrt{3}}{2} = 6\sqrt{3}$
Step2: Find y via 30-60-90 triangle
$y = 12 \times \frac{1}{2} = 6$
Problem 41
Step1: Find y via 30-60-90 ratios
$y = 6 \times 2 = 12$
Step2: Find x via 30-60-90 ratios
$x = 6\sqrt{3}$
Problem 42
Step1: Find x via 45-45-90 triangle
$x = 2\sqrt{2}$
Step2: Find y via 30-60-90 triangle
$y = 2 \times 2 = 4$
Step3: Find z via Pythagorean theorem
$z = \sqrt{(4+2)^2 + (6\sqrt{3})^2} = \sqrt{36 + 108} = \sqrt{144} = 12$
Problem 43
Step1: Find y via 45-45-90 triangle
$y = 44 \times \frac{\sqrt{2}}{2} = 22\sqrt{2}$
Step2: Find x via sine of 60°
$\sin(60^\circ) = \frac{22\sqrt{2}}{x} \implies x = \frac{22\sqrt{2}}{\frac{\sqrt{3}}{2}} = \frac{44\sqrt{6}}{3}$
Step3: Find z via cosine of 60°
$\cos(60^\circ) = \frac{z}{x} \implies z = \frac{44\sqrt{6}}{3} \times \frac{1}{2} = \frac{22\sqrt{6}}{3}$
Problem 44
(Answers already provided as $x=8\sqrt{2}$, $y=16$)
Problem 45
Step1: Find x via sine of 60°
$\sin(60^\circ) = \frac{12}{x} \implies x = \frac{12}{\frac{\sqrt{3}}{2}} = 8\sqrt{3}$
Step2: (y already provided as 12)
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- $x=17\sqrt{3}$, $y=34$
- $x=12$, $y=12\sqrt{2}$
- $x=6\sqrt{15}$, $y=12\sqrt{15}$
- $x=6\sqrt{3}$, $y=6$
- $x=6\sqrt{3}$, $y=12$
- $x=2\sqrt{2}$, $y=4$, $z=12$
- $x=\frac{44\sqrt{6}}{3}$, $y=22\sqrt{2}$, $z=\frac{22\sqrt{6}}{3}$
- $x=8\sqrt{2}$, $y=16$
- $x=8\sqrt{3}$, $y=12$