Question

1. jan opens a savings account with $200. each month, she deposits $225 into her account and does not withdraw any money from it.

a) write an equation in slope - intercept form of the total amount, y, in juanitas account after x months.
b) graph the function. label the axes and scale.
graph grid is shown here
c) how much money will juanita have in her savings account after 5 months?

1. graph the equation that has a slope of \\(\frac{1}{2}\\) & y - intercept of - 3.

graph grid is shown here

Explanation:

Part a)

Step1: Identify slope and intercept

The initial amount (y - intercept, \( b \)) is $200. The monthly deposit (slope, LXI1) is $25. The slope - intercept form is \( y=mx + b \).
\( y = 25x+200 \)

Step2: No further calculation for equation

The equation representing the total amount \( y \) in Juanita's account after \( x \) months is derived from the slope - intercept form with \( m = 25 \) and \( b = 200 \).

Step1: Substitute \( x = 5 \) into the equation

We use the equation \( y=25x + 200 \) from part (a). Substitute \( x = 5 \) into the equation.
\( y=25\times5 + 200 \)

Step2: Calculate the value of \( y \)

First, calculate \( 25\times5=125 \). Then, add 200 to the result: \( 125 + 200=325 \).

Answer:

\( y = 25x + 200 \)

Part c)