Question

3cu²⁺ + 2cr → 2cr³⁺ + 3cu
which of these represents the line notation of the spontaneous cell?
a. cu | cu²⁺(1.0 m) || cr³⁺(1.0 m) | cr
b. cu²⁺(1.0 m) | cu || cr | cr³⁺(1.0 m)
c. cr | cr³⁺(1.0 m) || cu²⁺(1.0 m) | cu
d. cr³⁺(1.0 m) | cr || cu | cu²⁺(1.0 m)
enter the answer choice letter.

Explanation:

1. First, identify the oxidation and reduction half - reactions from the given redox reaction \(3Cu^{2+}+2Cr

ightarrow2Cr^{3+}+3Cu\).

• Oxidation is the loss of electrons. For \(Cr\), the reaction is \(Cr

ightarrow Cr^{3+}+3e^-\) (oxidation, anode reaction).

• Reduction is the gain of electrons. For \(Cu^{2+}\), the reaction is \(Cu^{2+}+2e^-

ightarrow Cu\) (reduction, cathode reaction).

1. In line notation, the anode (where oxidation occurs) is written on the left, and the cathode (where reduction occurs) is written on the right. The anode is \(Cr\) (undergoing oxidation to \(Cr^{3+}\)) and the cathode is \(Cu^{2+}\) (undergoing reduction to \(Cu\)). So the line notation should have \(Cr|Cr^{3 +}(1.0 M)||Cu^{2+}(1.0 M)|Cu\).

Answer:

C