Question

3h₃po₄ phosphoric acid element h p o how many atoms 2h₂so₄ sulfuric acid - found in car batteries element h s o how many atoms c₆h₁₂o₆ glucose - a type of sugar element c h o how many atoms

Explanation:

Step1: Analyze $3H_3PO_4$

For hydrogen ($H$) in $3H_3PO_4$, the sub - script is 3 and the coefficient is 3, so the number of $H$ atoms is $3\times3 = 9$. For phosphorus ($P$), the sub - script is 1 and the coefficient is 3, so the number of $P$ atoms is $1\times3=3$. For oxygen ($O$), the sub - script is 4 and the coefficient is 3, so the number of $O$ atoms is $4\times3 = 12$.

Step2: Analyze $2H_2SO_4$

For hydrogen ($H$) in $2H_2SO_4$, the sub - script is 2 and the coefficient is 2, so the number of $H$ atoms is $2\times2=4$. For sulfur ($S$), the sub - script is 1 and the coefficient is 2, so the number of $S$ atoms is $1\times2 = 2$. For oxygen ($O$), the sub - script is 4 and the coefficient is 2, so the number of $O$ atoms is $4\times2=8$.

Step3: Analyze $C_6H_{12}O_6$

For carbon ($C$) in $C_6H_{12}O_6$, the number of atoms is 6. For hydrogen ($H$), the number of atoms is 12. For oxygen ($O$), the number of atoms is 6.

Answer:

Compound	Element	Number of Atoms
$3H_3PO_4$	$P$	3
$3H_3PO_4$	$O$	12
$2H_2SO_4$	$H$	4
$2H_2SO_4$	$S$	2
$2H_2SO_4$	$O$	8
$C_6H_{12}O_6$	$C$	6
$C_6H_{12}O_6$	$H$	12
$C_6H_{12}O_6$	$O$	6