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Question
- (3x + 20)° (x + 10)° type: x = - 5 7) x + 34° 2x - 12° type: x = 10) 3x + 21° x + 57° type: x = 11) x + 64° 3x - 26° type: x =
Step1: Identify vertical - angle relationship for problem 7
Vertical angles are equal. So, $2x - 12=x + 34$.
Step2: Solve the equation for $x$
Subtract $x$ from both sides: $2x-x-12=x - x+34$, which simplifies to $x-12 = 34$. Then add 12 to both sides: $x=34 + 12$.
Step3: Identify vertical - angle relationship for problem 10
Vertical angles are equal. So, $3x+21=x + 57$.
Step4: Solve the equation for $x$
Subtract $x$ from both sides: $3x - x+21=x - x+57$, which simplifies to $2x+21 = 57$. Then subtract 21 from both sides: $2x=57 - 21=36$. Divide both sides by 2: $x = 18$.
Step5: Identify corresponding - angle relationship for problem 11
Corresponding angles are equal. So, $x + 64=3x-26$.
Step6: Solve the equation for $x$
Subtract $x$ from both sides: $x - x+64=3x - x-26$, which simplifies to $64=2x-26$. Add 26 to both sides: $64 + 26=2x$, so $90=2x$. Divide both sides by 2: $x = 45$.
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- Type: Vertical angles, $x = 46$
- Type: Vertical angles, $x = 18$
- Type: Corresponding angles, $x = 45$