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1 (3x - 1)° 1 58° (4x - 10)° 2 c d □m∠1=(4x - 10)° □m∠2 = 58° □x = 20 □…

Question

1
(3x - 1)°
1
58°
(4x - 10)°
2
c
d
□m∠1=(4x - 10)°
□m∠2 = 58°
□x = 20
□(3x - 1)°=(4x - 10)°
□∠1 = 58°
mark this and return

Explanation:

Step1: Use vertical - angle property

Since $\angle1$ and the $58^{\circ}$ angle are vertical angles, $\angle1 = 58^{\circ}$.

Step2: Set up equation

$(3x - 1)^{\circ}=58^{\circ}$, solve for $x$:
$3x-1 = 58$, $3x=59$, $x=\frac{59}{3}
eq20$. Also, $(3x - 1)^{\circ}$ and $(4x - 10)^{\circ}$ are vertical - angles, so $3x-1 = 4x - 10$, $x = 9$. And $m\angle2$ and the $58^{\circ}$ angle are corresponding angles, so $m\angle2 = 58^{\circ}$.

Answer:

$m\angle2 = 58^{\circ}$, $\angle1 = 58^{\circ}$