Question

(\frac{1}{2}(3x - 2)) (1.5x - 1 = .5x) (-1.5x) (crossed) (-1.5x) (right) (-1 =) (crossed) (-1x) (crossed) (circle with x at bottom right)

Explanation:

Step1: Simplify the left side

Using the distributive property \( \frac{1}{2}(3x - 2)=\frac{3}{2}x - 1 \)

Step2: Set up the equation

Assuming the equation is \( \frac{1}{2}(3x - 2)=\frac{1}{2}x \) (from the written steps), substitute the left side: \( \frac{3}{2}x - 1=\frac{1}{2}x \)

Step3: Subtract \( \frac{1}{2}x \) from both sides

\( \frac{3}{2}x-\frac{1}{2}x - 1=\frac{1}{2}x-\frac{1}{2}x \) which simplifies to \( x - 1 = 0 \)

Step4: Add 1 to both sides

\( x - 1+1 = 0 + 1 \) so \( x = 1 \)

Wait, let's re - do it properly with the original - looking steps. The left - hand side after distributing \( \frac{1}{2}(3x - 2) \) is \( 1.5x-1 \) (since \( \frac{3}{2}=1.5 \) and \( \frac{- 2}{2}=-1 \)). Let's assume the right - hand side is \( 0.5x \) (since \( \frac{1}{2}x = 0.5x \))

Step1: Start with the equation

\( 1.5x-1 = 0.5x \)

Step2: Subtract \( 0.5x \) from both sides

\( 1.5x-0.5x-1=0.5x - 0.5x \)
\( x-1 = 0 \)

Step3: Add 1 to both sides

\( x-1 + 1=0 + 1 \)
\( x = 1 \)

Answer:

\( x = 1 \)