Question

k(-4, 0), l(-8, 0), m(-9, -2), n(-3, -2) translate 6 units down 5 units right

Explanation:

Step1: Recall translation rule

For a point $(x,y)$ translated $a$ units right and $b$ units down, the new - point is $(x + a,y - b)$. Here $a = 5$ and $b = 6$.

Step2: Translate point K

For $K(-4,0)$, $x=-4$ and $y = 0$. The new $x$ - coordinate is $x+5=-4 + 5=1$, and the new $y$ - coordinate is $y - 6=0-6=-6$. So $K'=(1,-6)$.

Step3: Translate point L

For $L(-8,0)$, $x=-8$ and $y = 0$. The new $x$ - coordinate is $x + 5=-8+5=-3$, and the new $y$ - coordinate is $y - 6=0 - 6=-6$. So $L'=(-3,-6)$.

Step4: Translate point M

For $M(-9,-2)$, $x=-9$ and $y=-2$. The new $x$ - coordinate is $x + 5=-9 + 5=-4$, and the new $y$ - coordinate is $y - 6=-2-6=-8$. So $M'=(-4,-8)$.

Step5: Translate point N

For $N(-3,-2)$, $x=-3$ and $y=-2$. The new $x$ - coordinate is $x + 5=-3 + 5=2$, and the new $y$ - coordinate is $y - 6=-2-6=-8$. So $N'=(2,-8)$.

Answer:

$K':(1,-6)$, $L':(-3,-6)$, $M':(-4,-8)$, $N':(2,-8)$