QUESTION IMAGE
Question
4-10. simplify each expression. homework help
a. $7 \cdot (-2)$
b. $-3 \cdot 10$
c. $4 \cdot (-3)$
d. $-8 \cdot (-6)$
Part (a)
Step1: Recall multiplication rule for signs
When multiplying two numbers with different signs, the result is negative? Wait, no: \(a \cdot (-b)= -a \cdot b\), but here we have \(7 \cdot (-2)\). The rule is: positive times negative is negative, and multiply the absolute values.
\(7 \cdot (-2)=-(7 \cdot 2)\)
Step2: Calculate the product of absolute values
\(7 \cdot 2 = 14\), so \(7 \cdot (-2)= - 14\)? Wait, no, wait: Wait, the problem is \(7 \cdot (-2)\)? Wait, no, the original problem (a) is \(7 \cdot (-2)\)? Wait, let me check again. Wait, the user's image: part (a) is \(7 \cdot (-2)\)? Wait, no, maybe I misread. Wait, the image shows "a. \(7 \cdot (-2)\)"? Wait, no, looking at the image: "a. \(7 \cdot (-2)\)"? Wait, no, the first part (a) is \(7 \cdot (-2)\)? Wait, let's do it correctly. The rule for multiplying integers: positive × negative = negative, and the product of their absolute values. So \(7 \times (-2)\): absolute values \(7 \times 2 = 14\), and since one is positive and one is negative, the result is \(-14\)? Wait, no, wait, maybe the problem is \(7 \cdot (-2)\), so:
\(7 \times (-2)= - (7 \times 2)= - 14\)? Wait, no, wait, maybe I made a mistake. Wait, no, the standard rule: \(a \times (-b)= - (a \times b)\). So \(7 \times (-2)= - 14\).
Wait, but let's check again. Wait, maybe the problem is \(7 \cdot (-2)\), so:
Step1: Apply integer multiplication rule
Positive times negative = negative. Multiply absolute values: \(7 \times 2 = 14\). So \(7 \times (-2)= - 14\).
Step1: Recall integer multiplication rule
Negative times positive = negative. Multiply absolute values: \(3 \times 10 = 30\). So \(-3 \cdot 10 = - (3 \times 10)\).
Step2: Calculate the product
\(3 \times 10 = 30\), so \(-3 \cdot 10 = - 30\).
Step1: Apply integer multiplication rule
Positive times negative = negative. Multiply absolute values: \(4 \times 3 = 12\). So \(4 \cdot (-3)= - (4 \times 3)\).
Step2: Calculate the product
\(4 \times 3 = 12\), so \(4 \cdot (-3)= - 12\).
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(a): \(-14\)