QUESTION IMAGE
Question
y = -4 + 3\sqrt3{x + 6}
describe the transformations of the graph shown.
shifted down 4 units, horizontal compression by a factor of 3, and shifted 6 units left.
shifted down 4 units, vertically compressed by a factor of 3, and shifted 6 units left.
shifted down 4 units, vertically compressed by a factor of 3, and shifted 6 units right.
none of the above.
To determine the transformations of the function \( y = -4 + 3\sqrt[3]{x + 6} \), we start with the parent function \( y=\sqrt[3]{x} \).
Step 1: Horizontal Shift
For a cube root function \( y=\sqrt[3]{x - h} \), the graph shifts \( h \) units to the right if \( h>0 \) and \( |h| \) units to the left if \( h<0 \). In our function, we have \( x + 6=x-(- 6) \), so the graph of \( y = \sqrt[3]{x} \) is shifted 6 units to the left.
Step 2: Vertical Stretch/Compression
For a function \( y = a\sqrt[3]{x} \), if \( |a|>1 \), it is a vertical stretch by a factor of \( |a| \), and if \( 0<|a|<1 \), it is a vertical compression. Here, \( a = 3>1 \), so the graph is vertically stretched (or we can say vertically compressed by a factor of \( \frac{1}{3} \)? Wait, no. Wait, the coefficient \( a \) in front of the cube root function \( y=a\sqrt[3]{x} \) represents a vertical stretch by a factor of \( |a| \) when \( |a|>1 \) and vertical compression when \( 0 < |a|<1 \). But in our case, the function is \( y=3\sqrt[3]{x + 6}-4 \) (rewriting as \( y = 3\sqrt[3]{x+6}-4 \)). So the \( 3 \) in front of the cube root means a vertical stretch by a factor of 3? Wait, no, actually, the transformation for vertical stretch/compression: if we have \( y = a\cdot f(x) \), then if \( |a|>1 \), it is a vertical stretch by a factor of \( |a| \), and if \( 0<|a|<1 \), it is a vertical compression. But in the options, they mention "vertically compressed by a factor of 3". Wait, maybe there is a mis - naming. Wait, actually, when \( a = 3 \), the graph of \( y=\sqrt[3]{x} \) is vertically stretched by a factor of 3. But the options say "vertically compressed by a factor of 3". Wait, maybe the options have a mistake in terminology, but let's check the shift.
Step 3: Vertical Shift
For a function \( y=f(x)+k \), the graph shifts \( k \) units up if \( k > 0 \) and \( |k| \) units down if \( k<0 \). Here, \( k=-4 \), so the graph is shifted 4 units down.
Now let's analyze the options:
- Option 1: Says "horizontal compression by a factor of 3". But the horizontal transformation is a shift, not a compression. The horizontal compression would be of the form \( y=\sqrt[3]{bx} \) where \( b > 1 \), but we have \( x+6 \), not \( bx \). So option 1 is wrong.
- Option 2: "Shifted down 4 units, vertically compressed by a factor of 3, and shifted 6 units left". Wait, the vertical coefficient is 3, which is a vertical stretch (or if we consider compression, it's a stretch, but maybe the option uses "compressed" incorrectly, but let's check the other parts. The vertical shift: down 4, horizontal shift: left 6. The vertical part: the coefficient 3 in front of the cube root. If we consider the transformation from \( y = \sqrt[3]{x+6} \) to \( y=3\sqrt[3]{x + 6} \), it's a vertical stretch by a factor of 3, but the option says "vertically compressed by a factor of 3". Wait, maybe the option has a terminology mix - up, but let's check the other options.
- Option 3: Says "shifted 6 units right". But we have \( x + 6\), which is a shift left, so option 3 is wrong.
Wait, but the correct transformations are: shifted 6 units left (because of \( x+6 \)), vertically stretched (or "compressed" in the option's terms, maybe they consider it as a compression in reverse) by a factor of 3 (because of the 3 in front), and shifted down 4 units (because of the - 4). So option 2 is the closest, as the horizontal shift is left 6, vertical shift is down 4, and the vertical coefficient is 3 (even though the term "compressed" might be misused, but the other options have wrong horizontal/…
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B. Shifted down 4 units, vertically compressed by a factor of 3, and shifted 6 units left.