Question

40.0 ml of 1.0 m hcl is added to a coffee cup. then 0.486 g mg are added. what is the mass of the solution?
d_{hcl} = 1.02 g/ml
mass_{hcl} = \frac{40.0\\ \text{ml}}{1} \times \frac{1.02\\ \text{g}}{\text{ml}} = 40.8\\ \text{g}
mass_{soln} = 40.8\\ \text{g} + 0.486\\ \text{g}
mass_{soln} = ?\\ \text{g}

Explanation:

Step1: Identify the masses to add

We have the mass of the HCl solution as 40.8 g and the mass of Mg as 0.486 g.

Step2: Add the two masses

To find the mass of the solution, we add the mass of the HCl solution and the mass of Mg. So, we calculate \(40.8\space g + 0.486\space g\).
\[40.8 + 0.486 = 41.286\]

Answer:

41.286