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42. using midpoints in the diagram below, b is the mid - point of $over…

Question

  1. using midpoints in the diagram below, b is the mid - point of $overline{ac}$, $ab = 9$, and $ad = 25$. find $cd$.
  2. challenge the mid - point of $overline{ab}$ is $m(7,5)$. the coordinates of point a are $(4,1)$. find the coordinates of point b. explain.
  3. multiple choice t is the mid - point of $overline{qr}$. what is the value of x? a 17 b 22 c 29.5 d 88
  4. multiple choice what is the mid - point of the segment joining $(2,7)$ and $(-6,2)$? f $(-2,\frac{9}{2})$ g $(-4,9)$ h $(-2,4)$ j $(\frac{9}{2},-2)$

mixed review evaluating statements use the diagram at the right to determine whether the statement is true or false. (lessons 1.3, 1.5)

  1. point a lies on line m.
  2. point e lies on line l.
  3. points b, e, and c are collinear.
  4. lines l and m intersect at point e.
  5. point e is between points b and c.
  6. point f is between points a and b.

classifying angles name the vertex and sides of the angle. then state whether it appears to be acute, right, obtuse, or straight. (lesson 1.6)
52.
53.
54.
algebra skills evaluating expressions evaluate the expression. (skills review, p. 670)

  1. $2cdot15 + 40$
  2. $120-35cdot3$
  3. $\frac{1}{2}cdot50 + 145$
  4. $\frac{5}{4}cdot16 - 20$
  5. $6 + 3cdot5-2$
  6. $11cdot4 + 7-20$
  7. $12cdot2-3cdot4$
  8. $5-10cdot6 + 1$
  9. $2-(3 + 4)cdot5$

Explanation:

Response
42.

Step1: Use mid - point property

Since \(B\) is the mid - point of \(\overline{AC}\), then \(AB = BC\). Given \(AB = 9\), so \(BC=9\).

Step2: Calculate \(CD\)

We know that \(AD = 25\), and \(AD=AB + BC+CD\). Substituting the known values: \(25=9 + 9+CD\). Then \(CD=25-(9 + 9)=7\).

Step1: Use mid - point property

Since \(T\) is the mid - point of \(\overline{QR}\), then \(QT=TR\). So \(4x-10 = 78\).

Step2: Solve for \(x\)

Add \(10\) to both sides of the equation: \(4x=78 + 10=88\). Then divide both sides by \(4\): \(x = 22\).

Step1: Recall mid - point formula

The mid - point formula for two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(M(\frac{x_1+x_2}{2},\frac{y_1 + y_2}{2})\). Here \(x_1 = 2,y_1 = 7,x_2=-6,y_2 = 2\).

Step2: Calculate the mid - point

For the \(x\) - coordinate: \(\frac{2+( - 6)}{2}=\frac{2 - 6}{2}=-2\). For the \(y\) - coordinate: \(\frac{7 + 2}{2}=\frac{9}{2}\).

Answer:

\(7\)

43.

Let the coordinates of point \(B\) be \((x,y)\). The mid - point formula for two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(M(\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})\).
We have \(x_1 = 4,y_1 = 1\) and \(M(7,5)\).
For the \(x\) - coordinate of the mid - point: \(\frac{4 + x}{2}=7\), then \(4+x = 14\), and \(x = 10\).
For the \(y\) - coordinate of the mid - point: \(\frac{1 + y}{2}=5\), then \(1 + y=10\), and \(y = 9\).
So the coordinates of point \(B\) are \((10,9)\).

44.