Question

1. a bag contains x blue chips and y red chips. if the probability of selecting a red chip at random is 3/7, then x/y = f. 7/11 g. 3/4 h. 7/4 i. 4/3 j. 11/7

Explanation:

Step1: Recall probability formula

The probability of selecting a red chip is $P(\text{red})=\frac{y}{x + y}$. Given $P(\text{red})=\frac{3}{7}$, so $\frac{y}{x + y}=\frac{3}{7}$.

Step2: Cross - multiply

Cross - multiplying gives $7y=3(x + y)$.

Step3: Expand and simplify

Expand: $7y = 3x+3y$. Then subtract $3y$ from both sides: $7y-3y=3x$, which simplifies to $4y = 3x$.

Step4: Solve for $\frac{x}{y}$

Dividing both sides of $4y = 3x$ by $3y$ (assuming $y
eq0$), we get $\frac{x}{y}=\frac{4}{3}$.

Answer:

I. $\frac{4}{3}$