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3. 4(49)= angela 4(40+9) 4(40)+(9) 180+36=196

Question

  1. 4(49)= angela 4(40+9) 4(40)+(9) 180+36=196

Explanation:

Step1: Identify the error in distribution

The original step \(4(40 + 9)=4(40)+(9)\) is incorrect. The distributive property states \(a(b + c)=ab+ac\), so it should be \(4(40 + 9)=4\times40+4\times9\).

Step2: Correctly apply distributive property

First, calculate \(4\times40 = 160\) and \(4\times9=36\).

Step3: Add the results

Then, add these two results: \(160 + 36=196\) (the final answer is correct, but the middle step had a distributive error). To redo the correct steps:

  • Step 1: Apply distributive law: \(4(49)=4(40 + 9)=4\times40+4\times9\)
  • Step 2: Calculate each product: \(4\times40 = 160\), \(4\times9 = 36\)
  • Step 3: Sum the products: \(160+36 = 196\)

Answer:

The correct calculation steps are \(4(49)=4(40 + 9)=4\times40+4\times9 = 160+36=196\) (note: the final answer is correct, but the initial distribution step had an error in the coefficient of 9, which should be 4, not 1). The final result is \(\boldsymbol{196}\).