Question

b(t) = 4t³ - t²
evaluate b(-2)
type answer here.

Explanation:

Step1: Substitute \( t = -2 \) into \( b(t) \)

\( b(-2) = 4(-2)^3 - (-2)^2 \)

Step2: Calculate powers

\( (-2)^3 = -8 \), \( (-2)^2 = 4 \), so \( b(-2) = 4\times(-8) - 4 \)

Step3: Perform multiplications and subtraction

\( 4\times(-8) = -32 \), then \( -32 - 4 = -36 \)

Answer:

\(-36\)