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-4x(2x^2 - 3x + 5)

Question

-4x(2x^2 - 3x + 5)

Explanation:

Step1: Distribute $-4x$ to first term

$-4x \times 2x^2 = -8x^3$

Step2: Distribute $-4x$ to second term

$-4x \times (-3x) = 12x^2$

Step3: Distribute $-4x$ to third term

$-4x \times 5 = -20x$

Step4: Combine all resulting terms

$-8x^3 + 12x^2 - 20x$

Answer:

$-8x^3 + 12x^2 - 20x$