Question

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$$\begin{cases} 4y = 1 \\ 8x - 4y = 3 \\ \\end{cases}$$

Explanation:

Step1: Solve for \( y \) from the first equation

From \( 4y = 1 \), we divide both sides by 4.
\( y=\frac{1}{4} \)

Step2: Substitute \( y \) into the second equation

Substitute \( y = \frac{1}{4} \) into \( 8x - 4y = 3 \).
\( 8x - 4\times\frac{1}{4}=3 \)
Simplify the left - hand side: \( 8x - 1 = 3 \)

Step3: Solve for \( x \)

Add 1 to both sides of the equation \( 8x - 1 = 3 \):
\( 8x=3 + 1=4 \)
Divide both sides by 8: \( x=\frac{4}{8}=\frac{1}{2} \)

Answer:

\( x = \frac{1}{2} \), \( y=\frac{1}{4} \)