Question

5-6.
write out the sum and calculate: $sum_{k=2}^{6} (k - 2)^2$

Explanation:

Step1: Expand the summation

$\sum_{k=2}^{6} (k-2)^2 = (2-2)^2 + (3-2)^2 + (4-2)^2 + (5-2)^2 + (6-2)^2$

Step2: Simplify each term

$= 0^2 + 1^2 + 2^2 + 3^2 + 4^2$

Step3: Calculate squared values

$= 0 + 1 + 4 + 9 + 16$

Step4: Sum the results

$= 25$

Answer:

25