Question

1. 4(a² + 5a - 6) - 3(2a³ + 4a - 5) =

Explanation:

Step1: Distribute coefficients to terms

$4(a^2 + 5a - 6) = 4a^2 + 20a - 24$
$-3(2a^2 + 4a - 5) = -6a^2 - 12a + 15$

Step2: Combine all expanded terms

$4a^2 + 20a - 24 - 6a^2 - 12a + 15$

Step3: Combine like terms

$(4a^2 - 6a^2) + (20a - 12a) + (-24 + 15)$
$=-2a^2 + 8a - 9$

Answer:

$-2a^2 + 8a - 9$