Question

1. if ∠5 = 5z - 20 and ∠8 = 3z + 10 are alternate exterior angles, solve for z.

a. 25
b. 15
c. 10
d. 20

Explanation:

Step1: Recall property of alternate exterior angles

Alternate exterior angles are equal. So, $5z - 20=3z + 10$.

Step2: Isolate variable terms

Subtract $3z$ from both sides: $5z-3z - 20=3z-3z + 10$, which simplifies to $2z-20 = 10$.

Step3: Isolate the variable

Add 20 to both sides: $2z-20 + 20=10 + 20$, getting $2z=30$.

Step4: Solve for z

Divide both sides by 2: $\frac{2z}{2}=\frac{30}{2}$, so $z = 15$. [Client Connection Error]

Answer:

A. 25