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Question
| x | y | ---- | ---- | $-\frac{pi}{2}$ | 0 | 0 | 6 | $\frac{pi}{2}$ | 0 | $pi$ | -6 | $\frac{3pi}{2}$ | 0 | the function represented by the table has the form $y = acos(bx)$. which of the following statements are true?choose three correct answers.1. the maximum value of the function is 6.2. the frequency is $\frac{1}{2pi}$3. the period is $pi$.4. the function increases on the interval $(pi, 2pi)$.5. the graph is compressed horizontally by a factor of $\frac{1}{2}$ |
Step1: Identify amplitude $a$
From the table, the maximum $y$-value is 6, so $a=6$.
Step2: Find period $T$
The function goes from maximum (at $x=0$) to minimum (at $x=\pi$) and back, so the full period is $2\pi$.
Step3: Calculate $b$ from period
Use $T=\frac{2\pi}{b}$, so $b=\frac{2\pi}{T}=\frac{2\pi}{2\pi}=1$. The function is $y=6\cos(x)$.
Step4: Verify each statement
- Max value is 6: True (matches $a=6$).
- Frequency is $\frac{1}{2\pi}$: Frequency $=\frac{1}{T}=\frac{1}{2\pi}$, True.
- Period is $\pi$: False (period is $2\pi$).
- Increases on $(\pi,2\pi)$: $\cos(x)$ increases on $(\pi,2\pi)$, so $6\cos(x)$ does too, True.
- Horizontal compression by $\frac{1}{2}$: $b=1$, no compression, False.
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- The maximum value of the function is 6.
- The frequency is $\frac{1}{2\pi}$.
- The function increases on the interval $(\pi, 2\pi)$.