Question

is (7, -6) a solution to this system of equations?
$y = \frac{1}{7}x + 7$
$x = 7$
yes
no

Explanation:

Step1: Substitute x - value into first equation

Given \(x = 7\) in the equation \(y=\frac{1}{7}x + 7\), substitute \(x = 7\):
\[y=\frac{1}{7}\times7+7\]
\[y = 1 + 7\]
\[y=8\]

Step2: Compare with given y - value

The given point is \((7,-6)\) where \(y=-6\), but from our calculation \(y = 8\) when \(x = 7\) in the first - equation.

Answer:

no