Question

1. in 45 seconds, how many more times does a newborns heart beat than a 6 - year - olds heart?

Explanation:

To solve this problem, we need to know the heart rate (beats per minute or beats per second) of a newborn and a 6 - year - old. Since this information is missing from the problem as presented, we can't calculate the number of times a newborn's heart beats more than a 6 - year - old's heart in 45 seconds.

If we assume the heart rate of a newborn is \(n\) beats per second and the heart rate of a 6 - year - old is \(s\) beats per second, the number of beats of a newborn in 45 seconds is \(45n\) and the number of beats of a 6 - year - old in 45 seconds is \(45s\). The difference in the number of beats is \(45n - 45s=45(n - s)\). But without the values of \(n\) and \(s\), we can't get a numerical answer.

For example, if a newborn's heart rate is 1.5 beats per second and a 6 - year - old's heart rate is 1 beat per second:

Step 1: Calculate the number of beats of the newborn in 45 seconds

The number of beats of the newborn \(=1.5\times45 = 67.5\)

Step 2: Calculate the number of beats of the 6 - year - old in 45 seconds

The number of beats of the 6 - year - old \(=1\times45=45\)

Step 3: Calculate the difference

The difference \(=67.5 - 45 = 22.5\)

But since we don't have the actual heart rates, we can't provide a definite answer. Please provide the heart rates (beats per second or beats per minute) of a newborn and a 6 - year - old to solve the problem.

Answer:

To solve this problem, we need to know the heart rate (beats per minute or beats per second) of a newborn and a 6 - year - old. Since this information is missing from the problem as presented, we can't calculate the number of times a newborn's heart beats more than a 6 - year - old's heart in 45 seconds.

If we assume the heart rate of a newborn is \(n\) beats per second and the heart rate of a 6 - year - old is \(s\) beats per second, the number of beats of a newborn in 45 seconds is \(45n\) and the number of beats of a 6 - year - old in 45 seconds is \(45s\). The difference in the number of beats is \(45n - 45s=45(n - s)\). But without the values of \(n\) and \(s\), we can't get a numerical answer.

For example, if a newborn's heart rate is 1.5 beats per second and a 6 - year - old's heart rate is 1 beat per second:

Step 1: Calculate the number of beats of the newborn in 45 seconds

The number of beats of the newborn \(=1.5\times45 = 67.5\)

Step 2: Calculate the number of beats of the 6 - year - old in 45 seconds

The number of beats of the 6 - year - old \(=1\times45=45\)

Step 3: Calculate the difference

The difference \(=67.5 - 45 = 22.5\)

But since we don't have the actual heart rates, we can't provide a definite answer. Please provide the heart rates (beats per second or beats per minute) of a newborn and a 6 - year - old to solve the problem.