Question

1\\
\frac{\cancel{4} \\ (6c + 4)}{\cancel{8}} = \\
\frac{6c + 4}{2} = \\
3c + 2 = \\
\underline{+ 2c} \\
\boxed{} =

Explanation:

Step1: Simplify the fraction

We start with \(\frac{4(6c + 4)}{8}\). First, simplify the fraction by dividing numerator and denominator by 4. So \(\frac{4(6c + 4)}{8}=\frac{6c + 4}{2}\) (since \(8\div4 = 2\) and \(4\div4 = 1\)).

Step2: Simplify \(\frac{6c + 4}{2}\)

Now, divide each term in the numerator by 2. \(\frac{6c}{2}+\frac{4}{2}=3c + 2\).

Step3: Add \(2c\) to \(3c + 2\)

To add \(3c + 2\) and \(2c\), we combine like terms. The like term of \(3c\) is \(2c\), so \(3c+2c + 2=(3 + 2)c+2 = 5c+2\).

Answer:

\(5c + 2\)