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Question
d. 7.74 x 10^26 formula units al₂o₃ to moles answer: 1.29 x 10³ mol al₂o₃
Step1: Recall Avogadro's number
1 mole = $6.022\times10^{23}$ formula - units
Step2: Calculate moles
$n=\frac{7.74\times 10^{26}}{6.022\times10^{23}}$ $\approx1.29\times 10^{3}$ mol
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$1.29\times 10^{3}$ mol $Al_{2}O_{3}$