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2. of 800 cars that drove on a street during a week, 0.75% exceeded the…

Question

  1. of 800 cars that drove on a street during a week, 0.75% exceeded the 25 miles per hour speed limit by more than 10 miles per hour. how many cars drove over 35 miles per hour? the number of cars driving over 35 miles per hour is \\(\frac{x}{800}\cdot\square=\frac{\square}{100}\cdot\square\\) \\(x=\frac{\square}{100}\\) \\(x=\square\\) drivers 4. when a bush was first planted in a garde it was 12 inches tall. after two weeks, it was 120% as tall as when it was first plan how tall was the bush after the two we

Explanation:

Response
Problem 2

Step1: Set up proportion

We know that the percentage of cars exceeding the speed limit is \(0.75\%\), and the total number of cars is \(800\). Let \(x\) be the number of cars driving over 35 mph. The proportion is \(\frac{x}{800}=\frac{0.75}{100}\) (rewriting the given equation structure \(\frac{x}{800}\cdot1 = \frac{0.75}{100}\cdot800\) for clarity, here the first blank is \(1\), the second blank in the numerator is \(0.75\), the last blank is \(800\)).

Step2: Solve for \(x\)

Cross - multiply: \(x=\frac{0.75\times800}{100}\)
First, calculate \(0.75\times800 = 600\)
Then, \(\frac{600}{100}=6\)

Step1: Understand the percentage increase

The initial height of the bush is \(12\) inches. After two weeks, it is \(120\%\) of its initial height. To find the new height, we use the formula: New height \(=\) Initial height \(\times\) Percentage (in decimal form)

Step2: Convert percentage to decimal

\(120\%=\frac{120}{100} = 1.2\)

Step3: Calculate the new height

Multiply the initial height by the decimal form of the percentage: \(12\times1.2 = 14.4\) inches

Answer:

For the equation \(\frac{x}{800}\cdot\boldsymbol{1}=\frac{\boldsymbol{0.75}}{100}\cdot\boldsymbol{800}\)
\(x = \frac{\boldsymbol{0.75\times800}}{100}\)
\(x=\boldsymbol{6}\) drivers

Problem 4