Question

1.890 g of benzoic acid, c₆h₅cooh, burns in a calorimeter. how many moles of benzoic acid go through combustion? ? mol c₆h₅cooh

Explanation:

Step1: Calculate molar mass of benzoic acid

Molar mass of \( C_6H_5COOH \):

• \( C \): \( 6 \times 12.01 = 72.06 \)
• \( H \): \( 6 \times 1.008 = 6.048 \)
• \( O \): \( 2 \times 16.00 = 32.00 \)

Sum: \( 72.06 + 6.048 + 32.00 = 122.108 \, g/mol \)

Step2: Use mass to find moles

Moles \( = \frac{\text{mass}}{\text{molar mass}} \)
Mass = \( 1.890 \, g \), Molar mass = \( 122.108 \, g/mol \)
Moles \( = \frac{1.890}{122.108} \approx 0.01548 \)

Answer:

\( 0.01548 \) (or more precise value from calculation, e.g., \( \approx 0.01548 \))