Question

\frac{(-4)^{2}+3\cdot2}{-9 + 4}
\bigcirc-\frac{38}{5}
\bigcirc-\frac{22}{5}
\bigcirc-\frac{19}{5}
\bigcirc2
question 8
7-|6 - 10|
\bigcirc-9
\bigcirc3
\bigcirc11
\bigcirc28

Explanation:

Step1: Solve first expression numerator

$$\begin{align*} (-4)^2 + 3 \cdot 2 &= 16 + 6 \\ &= 22 \end{align*}$$

Step2: Solve first expression denominator

$-9 + 4 = -5$

Step3: Simplify first expression

$\frac{22}{-5} = -\frac{22}{5}$

Step4: Solve absolute value in second expression

$|6 - 10| = |-4| = 4$

Step5: Calculate second expression

$7 - 4 = 3$

Answer:

First question: $-\frac{22}{5}$
Second question: 3