Question

1. 90° clockwise rotation

Explanation:

1. Recall the rotation rule for a \(90^{\circ}\) clock - wise rotation about the origin:

• The rule for a \(90^{\circ}\) clock - wise rotation of a point \((x,y)\) about the origin is \((x,y)\to(y, - x)\).

1. Assume the coordinates of the points \(E(x_E,y_E)\), \(F(x_F,y_F)\), \(G(x_G,y_G)\), and \(H(x_H,y_H)\) from the graph:

• Let's say \(E(-3,-2)\), \(F(0, - 3)\), \(G(2,-2)\), \(H(-3,0)\).

1. Apply the rotation rule to each point:

• For point \(E(-3,-2)\):
• Using the rule \((x,y)\to(y, - x)\), we substitute \(x=-3\) and \(y = - 2\). Then \(E'(-2,3)\).
• For point \(F(0,-3)\):
• Substitute \(x = 0\) and \(y=-3\) into the rule \((x,y)\to(y, - x)\). Then \(F'(-3,0)\).
• For point \(G(2,-2)\):
• Substitute \(x = 2\) and \(y=-2\) into the rule \((x,y)\to(y, - x)\). Then \(G'(-2,-2)\).
• For point \(H(-3,0)\):
• Substitute \(x=-3\) and \(y = 0\) into the rule \((x,y)\to(y, - x)\). Then \(H'(0,3)\).

Answer:

Point	Coordinates after \(90^{\circ}\) clock - wise rotation
\(F'\)	\((-3,0)\)
\(G'\)	\((-2,-2)\)
\(H'\)	\((0,3)\)