Question

1. (912.ar.1.2) the perimeter of any rectangle in which the length is 4 more than twice the width is p = 6w + 8, where w is the width. which formula can be used to find the width given the perimeter? a. w = p - \frac{4}{3} b. w = \frac{1}{6}p - 8 c. w = -\frac{p + 8}{6} d. w = \frac{p - 8}{6}

Explanation:

Step1: Isolate the term with \(w\)

Given \(P = 6w+8\), subtract 8 from both sides: \(P - 8=6w\).

Step2: Solve for \(w\)

Divide both sides by 6: \(w=\frac{P - 8}{6}\).

Answer:

D. \(w=\frac{P - 8}{6}\)