Question

ab = 3
bc = 3
bd = 9
ac = 6
cd = 6
ad = 12
you choose one of the segments at random. what is the probability that the measure of the segment is greater than 3?

Explanation:

Step1: Count total segments

There are 6 segments (AB, BC, BD, AC, CD, AD).

Step2: Count segments greater than 3

Segments BD = 9, AC = 6, CD = 6, AD = 12 are greater than 3. So there are 4 segments greater than 3.

Step3: Calculate probability

Probability = $\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}=\frac{4}{6}=\frac{2}{3}$

Answer:

$\frac{2}{3}$