acceleration
16. is it a vector or scalar?
17. what is the acceleration of a car that goes 0m/s to 20 m/s in 5s?
18. is an object accelerating when it is traveling2m/s down the road? explain
19. is the object accelerating when it is on a merry - go - round going 2 ms? explain
graphing
descriptions: place the letter of the graph that represents each statement.
1. the car is stopped.
2. the car is traveling at a constant speed.
3. the speed of the car is decreasing.
4. the car is coming back home

Question

Accepted Answer

### Question 16
# Brief Explanations:
Acceleration has both magnitude and direction (it depends on the change in velocity, which is a vector). So it is a vector quantity.
# Answer:
Vector

### Question 17
# Explanation:
## Step1: Recall the acceleration formula
The formula for acceleration $a$ is $a=\frac{v - u}{t}$, where $v$ is final velocity, $u$ is initial velocity, and $t$ is time.
## Step2: Substitute the values
Given $u = 0\space m/s$, $v=20\space m/s$, $t = 5\space s$. Substitute into the formula: $a=\frac{20 - 0}{5}$
## Step3: Calculate the result
$\frac{20}{5}=4\space m/s^{2}$
# Answer:
$4\space m/s^{2}$

### Question 18
# Brief Explanations:
Acceleration is the rate of change of velocity. Velocity includes speed and direction. If the object is traveling at a constant speed ($2\space m/s$) and direction (down the road) is constant, then velocity is constant. So acceleration is zero (no change in velocity), so it is not accelerating.
# Answer:
No, because its velocity (speed and direction) is constant. Acceleration is change in velocity, and here velocity isn't changing.

### Question 19
# Brief Explanations:
On a merry - go - round, even if the speed (magnitude of velocity) is constant ($2\space m/s$), the direction of motion is constantly changing. Since velocity is a vector (has magnitude and direction), a change in direction means a change in velocity. Acceleration is the rate of change of velocity, so the object is accelerating.
# Answer:
Yes, because the direction of its velocity is changing (even though speed is constant). Acceleration is change in velocity, and a change in direction of velocity means acceleration.

### Graphing Questions

#### 1. The car is stopped.
# Brief Explanations:
If a car is stopped, the distance it travels over time does not change. Graph A has distance constant with respect to time, so it represents a stopped car.
# Answer:
A

#### 2. The car is traveling at a constant speed.
# Brief Explanations:
For constant speed, distance is proportional to time ($d = vt$, where $v$ is constant). Graph B (and F, but B is a straight line from the origin, F is a straight line with a non - zero y - intercept, but both represent constant speed as the slope (speed) is constant) has a constant slope (distance vs time), so it represents constant speed. The most typical one for constant speed starting from rest is B, but F also has constant speed. However, usually, for a car starting its motion (or general constant speed), a straight line distance - time graph (constant slope) is used. So B (or F, but B is more typical for constant speed with $u = 0$, but the question just says constant speed).
# Answer:
B (or F, but B is a common choice for constant speed)

#### 3. The speed of the car is decreasing.
# Brief Explanations:
If speed is decreasing, the rate of change of distance (slope of distance - time graph) is decreasing. Graph E has a decreasing slope (the curve is getting less steep), which means speed (slope $=\frac{\Delta d}{\Delta t}$) is decreasing.
# Answer:
E

#### 4. The car is coming back home.
# Brief Explanations:
If a car is coming back home, the distance from home should be decreasing as time increases. Graph C has distance decreasing with time, so it represents a car coming back home.
# Answer:
C

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QUESTION IMAGE

Question

Explanation:

Question 16

Step1: Recall the acceleration formula

Step2: Substitute the values

Step3: Calculate the result

Answer:

Question 17